| A Week 1 Week 2 Flowrate Readings (gal /min) Flowrate Readings (gal min) Q 3 Q
ID: 2312506 • Letter: #
Question
| A Week 1 Week 2 Flowrate Readings (gal /min) Flowrate Readings (gal min) Q 3 Q3 2.78 5.33 2.82 5.38 7.12 2.91 5.38 2.96 5.33 7.08 7.03 2.87 5.386.99 2.91 5.33 2.96 5.38 2.965.336.94 3.05 5.29 6.9 7.03 12 10 Sum2.9095.346 7.033 10 Sum T.01 15 QavG 0.000184 0.000337 0.000444m/s Distanc0.026 0.0730131m Distance Vin 2.34 4.30 5.65 m/s #DIV/O! " #DIVO! #DIV/O! A (m) L (m) D (mm) Wmassg pg/m3 858 2898 5015 g g 7.85E-05 0.15 150 0.01 10 20 600 Distance (mm) 26 Distance (mm) 73 131 25 26 Conversion al/mi 6.31E-05 m/sec cm3 0.000001 HemispheeExplanation / Answer
you had calculated force based on the theoretical formula that is correct but you have to calculate on the basis of experiment formula which is given by-
F = Fw(dw2 - dw1)/do
where Fw = mg
m = mass of balance block
do = water jet distance from the pivot
dw1 = balance weight distance from pivot when water jet is not applied
dw2 = balance weight distance from pivot when water jet is applied
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