8 Problem 02.059-Apply a force triangle to the of equlibrium to a perticle -DEPE

Question

8 Problem 02.059-Apply a force triangle to the of equlibrium to a perticle -DEPENDENT MULTL PART PROBLEM- ASSIGN ALL PARTS Consider the figure in which -14. as shown 120b References Book& Resources Section Break Problem 02 059 . Apply force trwngle to the of e to o perticle DEPENDENT MULTHPART PROBLEM ASSIGN ALL PARTS Dimesity. 1000 points You did not rece ve full credit for this epa~tion ia previous mempt Reqdred omation Problem 02.059.a -Apply a force triangle to the of equilibrium to a particle Round the etermne the value a for which the tension in rope BC pait) mramum nal answer to the nearest Mole number You must ro dear we be re movin o to the nest The value or for which the tension in rope BCs minimum, is-ITT),

Explanation / Answer

*rope only can handel tension

balence force in vertical direction

FAC*Cos14 =1200 + FCB *Sin   -------------------------1

balence force in horizontal directio

FAC SIN14 = FCB Cos

FAC= FCB Cos /SIN14

PUT this value in equ 1

FCB Cos /SIN14*Cos14 =1200 + FCB *Sin

FCB*Cot 14*Cos = 1200+ FCB *Sin

4.01078*FCB *Cos - FCB *Sin = 1200

FCB (4.01078Cos - Sin) = 1200

FCB = 1200 / (4.01078Cos - Sin)

TO MINIMISE FCB (4.01078Cos - Sin) should be maximum

hence = 0o

minimum tension in rope BC

PUT =0 in above expression

FCB = 1200 / (4.01078Cos0 - Sin0) = 1200/4.01078 =299.2 lb = 299 lb

Related Questions

Navigate

• Browse (All)
• Browse 8
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.