A battery (6.0 V), initially uncharged capacitor (25 µF), resistor (150 ) and a

Question

A battery (6.0 V), initially uncharged capacitor (25 µF), resistor (150 ) and a switch are connected in series. The switch is closed at t = 0.

b.) After a long time (t=tL), a dielectric (with constant ) is suddenly inserted between the plates.
Which of the listed quantities will be different:
just before vs. just after the dielectric is inserted? (Select all that apply.)

A.charge on each plate

B.voltage difference across the plates

C.net electric field between the plates

D.electric field due to the plates alone

E.potential energy stored on the capacitor

ii.

just before the dielectric is inserted, vs. a long time after (t=tLL) the dielectric remains inserted? (Select all that apply.)

a.charge on each plate

b.voltage difference across the plates

c.net electric field between the plates

d.electric field due to the plates alone

e.potential energy stored on the capacitor

Explanation / Answer

B) as capacitor is still connected with battery hence Potential difference across the capacitor
will be same as 6V.

inserting dielectric will change the capacitance of capacitor.

C' = k C

(C' - new capacitance and C = old one)

and Q = C V

C changes but V is constant so Q also changes.

E = V/d  

V and d both are unchanged so E will also remain same.

PE = C V^2 /2  

C changes so stores PE will also changes.

charge on single plate is change so due to single plate Electric field also changes.

Ans. (A, D, E)

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