Three registor are connected in delta. If the line voltage is 13.2kv and the lin

Question

Three registor are connected in delta. If the line voltage is 13.2kv and the line current is 1202A, calculate the following A. The current run each registor B. The voltage across each registor C. The power supplied to each registor D. The power supplied to the 3-phase load E. The ohmic value of each registor Three registor are connected in delta. If the line voltage is 13.2kv and the line current is 1202A, calculate the following A. The current run each registor B. The voltage across each registor C. The power supplied to each registor D. The power supplied to the 3-phase load E. The ohmic value of each registor A. The current run each registor B. The voltage across each registor C. The power supplied to each registor D. The power supplied to the 3-phase load E. The ohmic value of each registor

Explanation / Answer

a. line current for a delta connected load is 3 * the phase current.

I_line = I_phase * 3
I_phase = I_line / 3 = 1202 A / 3 = 695 A

b. phase voltage for a delta connected load = line voltage

V_phase = V_line = 13.2 kV? (My browser is messing up the voltage you posted, so I'm guessing you meant it was 13.2 kV)

c. Power in each resistor = V_phase * I_phase

Power = 13.2 kV * 695 A = 9.17 MW

d. Total Power = 3 * V_line * I_line (for any 3-phase load, or Total Power = 3 * Power in each resistor)

Power = 3 * 13.2 kV * 1202 A = 27.5 MW

e. R = V_phase / I_phase

R = 13.2 kV / 695 A = 19

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