t) mover a large crate, (mass a 75 kg), the inside of a to the back end, distanc
ID: 2306326 • Letter: T
Question
t) mover a large crate, (mass a 75 kg), the inside of a to the back end, distance A of 300 from If the crate this i of 6 m), exerting a steady net Newtons. what is his power output during this time? (2) What must be the power output of an elevator motor that can lift a total mass of 1000 kg, and provide the elevator a constant speed of 8.0 m/s? (3) An individual runs up some steep stais, elevating his 105 kg body a vertical distance of 9.6 meters in 11.2 seconds. What was the power output? (4) A new conveyer system utilizes a motor-powered arm to exert an average force of 890 N to push large crates a distance of 12 meters in 22 seconds What is the power output required by such a motor? (5) An elevator is capable of transporting passengers at a speed of 16.8 m/s. The combined mass of the passengers and cart is 1390 kg. What power output required to deliver this many passengers at this isExplanation / Answer
Only one question can be answered in one posting, however as a special case question 1 and 2 and answered, please post each question separately. The image is of very poor quality to read.
(1)
Force applied F = 300N
Distance moved s= 6 m
Work done = Force x displacement
= 300*6 = 1800 Joules.
Work done is energy delivered.
Power is rate of work done or energy delivered per unit time.
The above work is done in 20 seconds
Power output = 1800/20 = 90 watts ( watt= joules/s)
(2)
Mass m = 1000 kg
Gravitational force acting on the mass = mg = 1000*9.8
= 9800 N
Elevator speed = 8.0 m/s
Distance moved in 1 s = 8.0 m
Work done in 1 s = 9800*8 = 78400 joules
Power output = 78400 watts.
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