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0 10 points SerCP719PO08. My Notes Ask Your Teache An electron is accelerated th

ID: 2305033 • Letter: 0

Question

0 10 points SerCP719PO08. My Notes Ask Your Teache An electron is accelerated through 2400 V from rest and then enters a region where there is a uniform 1.80 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? (a) maximum (b) minimum 0/10 points|Previous Answers SerCP7 19 P010.soln My Notes Ask Your Teache Sodium ions (Na+) move at 0.848 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.257 T and makes an angle of 62.0 with the motion of the sodium ions. The arm contains 80.0 cm3 of blood with 3.00 x 1020 Nat ions per cubic centimeter. If no other ions were present in the arm, what would be the magnetic force on the arm? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N

Explanation / Answer

1. KE = q delta(V)

and KE = m v^2 / 2

(9.109 x 10^-31) v^2 /2 = (1.6 x 10^-19)(2400)

v = 2.904 x 10^7 m/s

Fb = q (v X B)

Fb = q v B sin(theta)

(A) Fb_max = q v B { when theta = 90 deg , sin90 = 1}

Fb_max = (1.6 x 10^-19)(2.904 x 10^7)(1.80)

= 8.36 x 10^-12 N .....Ans

(B) when theta = 0 deg then sin0 = 0

so Fb_min = 0