r? 3 and see time I.-IK, below A tadent attaches a enall battery to a eotl of vi

Question

r? 3 and see time I.-IK, below A tadent attaches a enall battery to a eotl of vire vith one of his fingara touching the bare copper vire and one battery terminal wire and the other battery terninal. (See dring above) After and his thab touching the other end of tbe eopper the battery keeping the coil in his hand l during the time of the battery, he caretully removes The graph above representa the current floving through experiment. The tine axis bas been divided into several regions. Choose regions which best anave eammot be determined from tho data here given, u the letter N as the correot responae the regioan or er the questions below. Ir no region is applieable ar the item 1. In whieh region(a) vas the eurrent through the coil a naximm 2. In whieh regions) vas the magnetie field strengthma 3. Ia vhieh region(e) as the magnatio fteld atrength serot fnt nare themsainstent . Ia whieh region(o) vas the rate of change of magnetite f ield a mit . In which region(s) was the rate of change of magnetic field zero? 6. which region(a) was tho induced potential a maximun? 7. In which region(s) was the induced potential zero? or ward 8. In which region() was the induced potential in opposition to the pressed/potantial? 9. In which region(a) vas all the electrical energy put into tbe coil being converted ncreasn tle 10. In which region (s) did the stadentymake a shocking discovery? I. The time rate of change of magnetic field is proportional to the time rate of change of the forward current (that is, to the slope of an I vs. t graph): dB/dt ? dldi II. The self-induced potential difference is proportional to the negative of the time rate of change of current (that is, to the negative of the slope of an I vs. t graph) rys(Hit ?Vinduced=-Ldl/dt , where L is the or self-inductance in henrys (H). III. Time rate of change of energy in the magnetic field of the inductor: dUB /dt = Li di/dt IV. Time rate at which energy is being converted into internal energy of the resistance (and transferred as heat): P IR

Explanation / Answer

for the given situation

1. the graph shouws current as a function of time in the coil

so current was maximum in region B

2. magnetic field strench is proportional to current

so it is stronest in region B

3. magnetic field strength is 0 when current is 0, hence it is never 0 in any of the regions

4. dB/dt is maximum where di/dt is maximum, it is regions C

5. dB/dt = 0 when di/dt = 0

so, region B

6. V is proportional to dB/dt

so induced potential V is maximum in region C

7. induced potential is 0 in region B

8. in region A, di/dt is +ve but decreasing with time

hence the imposed potentil is opposite to the induced potentail in region A as induced potential is proportional to -di/dt

9. energy stored in inductor = Li^2/2

dE/dt = 0

when

Lidi/dt = 0

ence di/dt = 0 in region B, so all energy is consumed as heat in this region

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