Problem 1 The 300-uF capacitor in the figure on the right is initially charged t

Question

Problem 1 The 300-uF capacitor in the figure on the right is initially charged to 100 V, the 1200-uF capacitor is uncharged, and the switches are both open. a. What is the maximum voltage to which you can charge the S2 300 uFE 5.3 H F 1200 p.F 1200-uF capacitor by the proper closing and opening of the two switches? How would you do it? Describe the sequence in which you would close and open switches and the times at which you would do so. The first switch is closed at 1-0 b. [Answers: (a) 50.0 V (b) Think about this one! ]

Explanation / Answer

a)

By Conservation of energy

(1/2)C1V12 =(1/2)C2V22

300*1002=1200*V22

V22=2500

V2=50 V

b)

Close Switch S1 with switch S2 open forming an LC Circuit ,at the instant when the voltage across C1 is zero open switch S1 and close switch S2 forming a new LC circuit .The energy stored in C1 initially is transferred to Inductor L which is stored in its magnetic field .Open Switch S2 when the current in the new LC circuit falls to zero ,which leaves C2 with maximum voltage across it.

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