all questions answered and I\'ll rate thanks!! 7. A fountain sends strea in diam

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all questions answered and I'll rate thanks!!

7. A fountain sends strea in diameter, what power is required to send the water to this height? 3pt) a stream of water 20.0 m up into the air. If the hase of the stream is 10.9 cm 8. A hose has been clamped so that the area at the clamp is only one quarter the area of the rest of the hose. When we ignore the viscosity of water, what is the ratio of the speed of the water through the clamped area to the speed of the water when it leaves the hose? (3pt) Page 4 of 4

Explanation / Answer

Solutions:

7.

For the water molecules to go to the specified heighth,

use mv2/2 - mu2/2 = -mgh byconservation of energy

=> 0 - mu2/2 = mgh => u =?(2gh)

=> Initial kinetic energy = mu2/2 = mghfor each particle.

   Thus, the amount of power = Kinetic energy transferred/unit time

= Total mass * g * h / 1 W = Area * speed*density*9.8*19.8

=?*(0.10/2)2*?(2*9.8*20)*1000*9.8*20W

= 30462.725 W

8.

Since the velocity of the water increases when the hope is clamped so, The amount of water delivered per unit time with or without clamp is the same.

Hence, the ratio is equal to one.

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