Do not round intermediate calculations, however for display purposes report inte

Question

Do not round intermediate calculations, however for display purposes report intermediate steps rounded to four significant figures. Give your final answer(s) to four significant figures. Solve the problem below, assuming that the axle has been rotated clockwise in its bearings by 50° and that the 720-N load remains vertical. A 200-mm lever and a 240-mm-diameter pulley are welded to the axle BE that is supported by bearings atC and D. If a 720-N vertical load is applied at A when the lever is horizontal, determine

Explanation / Answer

So, the 720N force causes an anticlockwise moment of (720N * 0.2m) = 144 Nm about B.

The cord therefore must exert a clockwise moment of 144 Nm. The force required to do this given that T is 0.12 m away from the pivot point is F = (144Nm/0.12m) = 1200 N

Therefore, T = 1200 N

(b)

Reactions at C and D can be resolve into vertical and horizontal forces. Neglecting self-weight, the only external vertical force is the 720 N force, while the horizontal force is the 1200 N force.

Vertical Reactions:

D = 480 N downwards (sum of vertical moments about C = 0)

C = 1200 N upwards (sum of vertical forces acting on the axle = 0)

Horizontal Reactions:

C = 400 N in +x direction (sum of horizontal moments about D = 0)

D = 1600 N in -x direction (sum of horizontal forces acting on axle = 0)

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.