Please help with B MasteringPhysics: HW 4 Ch 23 and 24 Spring 2018-Google Chrome

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Please help with B MasteringPhysics: HW 4 Ch 23 and 24 Spring 2018-Google Chrome Secure https://session.masteringphysics.com/myct/itemView?assignmentProblemiD-96103271 HW 4 Ch 23 and 24 Spring 2018 Item 14 14 of 14 US Answers Constants When two lenses are used in combination, the first Correct one forms an image that then serves as the cbject for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object A 1 20 cm -tall object is 55 0 em to the left of a converging lens of focal length 40 0 cm A second converging lens this one having a focal length of 60 0 em is located 300 cm to the right of the fst lens along the same optic axis Part B is now the oblect for the second iens Find the location and height of the image produced by the lens iThis is the inal image produced by the combination of lenses Enter your answer as two numbers separated with a comma. 154.10 Submil X incorrect Try Again; attempts remaining S Return to Assignment 123 final epar Type here to search

Explanation / Answer

using lens formula,

1/f= 1/v-1/u

1/40= 1/v-(-1/55)

v= 146.67 cm

now object distance for second lens

u'= 300-146.67 cm= 153.33 cm

agian using lens formula

1/f' = 1/v'-1/u'

1/60= 1/v'-(-1/153.33)

v'= 98.57 cm (ans)

magnification, m=(v/u)(v'/u')= (146.77/55)(98.57/153.33)= h'/1.2

h'= 2.058 cm (ans)

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