Green light of wavelength 540 nm is incident on two slits that are separated by

Question

Green light of wavelength 540 nm is incident on two slits that are separated by 0.60mm .

Determine the frequency of the light.

What can you change in order to double the distance between the 0th and the first bright spot on the screen?

Choose all that apply.

f =

Determine the angles of the first two maxima of the interference pattern.
theta=

What can you change in order to double the distance between the 0th and the first bright spot on the screen?

Choose all that apply.

Choose all that apply. Double the separation between the screen and the slits. Double the slit separation. Reduce by one-half the separation between the screen and the slits. Reduce by one-half the slit separation.

Explanation / Answer

Part A)

Apply c = f(wavelength)

3 X 108 = f(540 X 10-9)

f = 5.56 X 1014 Hz

Part B)
tan(angle) = m(wavelength)/d

For first pattern

tan(angle) = 1(540 X 10-9)/(6 X 10-4)

angle = .0516 degrees

For the second pattern

tan(angle) = 2(540 X 10-9)/(6 X 10-4)

angle = .103 degrees

Part C)

The formula that governs this is y/L = m(wavelength)/d

That means to double the distance between the zeroth and first bright spot, you can...

Double the separation between the screen and the slits or Reduce by one-half the slit separation.

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