When viewing a piece of art that is behind glass, one often is affected by the l

Question

When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glass (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare.

A) If the glass has a refractive index of 1.58 and you use TiO2, which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 550nm ?

answer in nm

B)

If this coating is too thin to stand up to wear, what other thicknesses would also work? Find only the three thinnest ones.

Enter your answers in ascending order separated by a comma.

t2,t3,t4

answer in nm

Explanation / Answer

Part A)

Apply 2nt = m(wavelength)

2(2.62)(t) = (1)(550 X 10-9)

t = 1.05 X 10-7 m

That is 105 nm

Part B)

Apply 2nt = m(wavelength) and we will use m values of 2, 3, and 4

2(2.62)(t) = (2)(550 X 10-9)

t = 210 nm

2(2.62)(t) = (3)(550 X 10-9)

t = 315 nm

2(2.62)(t) = (4)(550 X 10-9)

t = 420 nm

Thus, 210 nm, 315 nm, 420 nm

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