Bear with me, burt for some reason it isn\'t letting me upload this image from w

Question

Bear with me, burt for some reason it isn't letting me upload this image from word. so i can't show a picture of the transistors only where the ohms are on the resisters. I'm sorry about this.

ok

Consider the combinations of resistors shown in the figure below:

Resistor 1 Resistor 2

12-ohms 4.0-ohms

a-------[ ]-----5.0-ohms-----[ ]----------b

6.0-ohms 8.0-ohms

a) Find the equivalent resistance between point A and point B.

b) If a voltage of 43.5 V is applied between points A and B, find the current in each resistor.

Explanation / Answer

a) The equivalent resistance for the first two is: 1/Rep1=1/R1 + 1/R2 => Rep1 = 6*12/(6+12)=4 ?
for the last two we apply the same formula : Rep2=4*8/(4+8)=8/3 ?.

Ok now the Re = Rep1 + Rep2 + R = 4 + 8/3 + 5 = 9 + 8/3 = 35/3 ?.

b) Now we can apply the Law of Ohm : U = I*Re.
We know know the value of Re.
So I=U/Re => I=2,01 A. So the resistance of 5 ? will have this value for I.
Now for the others. We consider i1 for 12, i2 for 6. i1*12 = i2*6, and i1+i2=I
The same goes for the last two : i3 for 4 and i4 for 8. So i3*4=i4*8 and i3+i4=I.
You have to solve those two systems and find those values, but this is very simple.

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