%3Cdiv%20class%3D%22page%22%20title%3D%22Page%209%22%3E%0A%3Cdiv%20class%3D%22se

Question

%3Cdiv%20class%3D%22page%22%20title%3D%22Page%209%22%3E%0A%3Cdiv%20class%3D%22section%22%3E%0A%3Cdiv%20class%3D%22layoutArea%22%3E%0A%3Cdiv%20class%3D%22column%22%3E%0A%3Cp%3E%3Cspan%20class%3D%22c1%22%3EA%20long%20solenoid%20with%20a%20radius%20of%3C%2Fspan%3E%0A%3Cspan%20class%3D%22c2%22%3E3.2%3C%2Fspan%3E%20%3Cspan%20class%3D%22c1%22%3Ecm%20has%3C%2Fspan%3E%0A%3Cspan%20class%3D%22c2%22%3E700%3C%2Fspan%3E%20%3Cspan%20class%3D%22c1%22%3Eturns%20per%20meter.%20If%0Athe%20current%20in%20the%20solenoid%20is%20decreasing%20at%20a%20rate%20of%3C%2Fspan%3E%0A%3Cspan%20class%3D%22c2%22%3E8.0%3C%2Fspan%3E%20%3Cspan%20class%3D%22c1%22%3EA%2Fs%2C%20what%20is%20the%0Amagnitude%20of%20the%20induced%20electric%20field%20at%20a%20point%20which%20is%3C%2Fspan%3E%0A%3Cspan%20class%3D%22c2%22%3E4.0%3C%2Fspan%3E%20%3Cspan%20class%3D%22c1%22%3Ecm%20from%20the%20axis%20of%0Athe%20solenoid%3F%20%3C%2Fspan%3E%3C%2Fp%3E%0A%3C%2Fdiv%3E%0A%3C%2Fdiv%3E%0A%3C%2Fdiv%3E%0A%3C%2Fdiv%3E%0A

Explanation / Answer

E = -d(N?)/dt = -L dI/dt given dI/dt = 8A/s

L = (?N^2A)/l
?0 = 4? x 10-7 T m/A
N = 700*0.04= 28
A = pi (0.032)^2 = 0.0101 l = 0.04

L = 497.52*10^-6

E =8*497.52*10^-6 E=3980.16*10^-6volt

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