%3Cdiv%20id%3D%22page%22%3E%0A%3Cdiv%3ETwo%20skydivers%20are%20holding%20on%20to

Question

%3Cdiv%20id%3D%22page%22%3E%0A%3Cdiv%3ETwo%20skydivers%20are%20holding%20on%20to%20each%20other%20while%20falling%0Astraight%20down%20at%20a%20common%20terminal%20speed%20of%2053.5%20m%2Fs.%20Suddenly%2C%0Athey%20push%20away%20from%20each%20other.%20Immediately%20after%20separation%2C%20the%0Afirst%20skydiver%20(who%20has%20a%20mass%20of%2083.8%20kg)%20has%20the%20following%0Avelocity%20components%20(with%20%5C%22straight%20down%5C%22%20corresponding%20to%20the%0Apositive%20z-axis)%3A%3Cbr%20%2F%3E%0A%3Cbr%20%2F%3E%0AV1x%3A%205.43%20m%2Fs%3Cbr%20%2F%3E%0AV1y%3A%203.75%20m%2Fs%3Cbr%20%2F%3E%0AV1z%3A%2053.5%20m%2Fs%3Cbr%20%2F%3E%0A%3Cbr%20%2F%3E%0AWhat%20are%20the%20x-%20and%20y-components%20of%20the%20velocity%20of%20the%20second%0Askydiver%2C%20whose%20mass%20is%2057.7%20kg%2C%20immediately%20after%0Aseparation%3F%3Cbr%20%2F%3E%0AWhat%20is%20the%20change%20in%20kinetic%20energy%20of%20the%20system%3F%3Cbr%20%2F%3E%3C%2Fdiv%3E%0A%3C%2Fdiv%3E%0A

Explanation / Answer

v2x = 5.43m/s * 83.8/57.7 = 7.8862 m/s
v2y = 3.75m/s * 83.8/57.7 = 5.4462 m/s
v2z = 53.5 m/s

For second diver, KEi =

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