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The Reaction Quotient 50f 14 >: Part A Ammonia can be produced via the chemical

ID: 229684 • Letter: T

Question

The Reaction Quotient 50f 14 >: Part A Ammonia can be produced via the chemical reaction N2(g) + 3H2(g) 2NH3 (g) When conducting chemical reactions in the lab or in industrial processes, it can be important to know whether a reaction has reached equilibrium. By measuring the reaction quotient, Q, of a chemical reaction and comparing it to the equilibrium constant, K, we can identify whether a reaction is at equilibrium. During the production process, the production engineer determines the reaction quotient to be Q 3.56x104 f K 6.02102, what can be said about the reaction? View Available Hint(s) For the reaction The reaction has reached equilibrium. The reaction is not at equilibrium and will proceed to the left. O The reaction is not at equilibrium and will proceed to the right. the reaction quotient, Q, is given by the expression The reaction is not at equilibrium, but it is not possible to determine whether the reaction needs to proceed right or left to reach equilibrium. under any conditions. The value of Q is equal to K only at Submit Part B The following reaction was carried out in a 2.25 L reaction vessel at 1100 K: C(s) +H2O(g)CO(g) +H2(g) If during the course of the reaction, the vessel is found to contain 6.00 mol of C, 15.2 mol of H2 O, 3.70 mol of CO, and 7.50 mol of H2, what is the reaction quoient Q? Enter the reaction quotient numerically View Available Hint(s)

Explanation / Answer

N2(g) + 3H2(g) <-----> 2 NH3(g)

At equilibrium Kc = [NH3]^2/[N2][H2]^3 = 6.02*10^-2

and the Reaction Quotiant Qc = [NH3]^2/[N2][H2]^3 = 3.56*10^-4

so Qc < Kc which indicate [NH3] < [N2]and[Ha}, so the reaction moves forward direction i.e., towards right to reach equilibrium

C(s) + H2O(g) <------> CO(g) + H2(g)

Qc = [CO][H2]/[C][H2O]

Qc = (6/2.25)*(15.2/2.25)/((3.7/2.25)*(7.5/2.25))

Qc = 3.2865

2CH4(g) <----> C2H2(g) + 3H2(g)

QC = [C2H2][H2]^3/[CH4]^2

Qc = ((4.8/5.2)*(10.05/5.2)^3)/(6.3/5.2)^2

Qc = 4.54

Qc > Kc so [C2H2] and [H2] are more compare to [CH4] hence the rection moves in backward direction i.e., towards lesft

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