for (c) through (e) E = 12V and R = 200 Omega C) Calculate the equivalent resist
ID: 2295662 • Letter: F
Question
for (c) through (e) E = 12V and R = 200 Omega
C) Calculate the equivalent resistance of the circuit.
D) calculate the current in resistor R_c.
e)the switch S is opened, resistor R_B is removed and replaced by a capacitor of capacitance 2.0x10E-6F, and switch S is closed again. Calc. the charge on a capacitor after all the currents have reached their final steady-state values.
AP* Physics B Electric Circuits Name: Period . The circuit above contains a battery with negligible internal resistance, a closed switch S. and three resistors, each with a resistance of R or 2R. (a) Rank the currents in the three resistors from greatest to least, with number 1 being greatest. It two resistors have the same current, give them the same ranking. IA IB IC Justify your answers. (b) Rank the voltages across the three resistors from greatest to least, with number I being greatest If two resistors have the same voltage across them, give them the same ranking. VA VB VC Justify your answers.Explanation / Answer
Rc and Rb are in parallel
1/Rbc = 1/Rb + 1/Rc = 1/2R + 1/R = 3/2R
Rbc = 2R/3
Rbc and Ra are in series
so equvalent resistance Req = Rbc + Ra = 2R/3 + 2R = 8R/3 8*200/3= 534 ohms
toal current I = Ia = e/Req = 12/534 = 22.5 mA
Va = Ia*Ra = 9 v
Vb = Vc = e-Va = 3V
Ib = Vb/Rb = 7.5 mA
Ic = Vc/Rc = 15 mA
a) Ia > Ic > Ib
b) Va > Vb = Vc
C) Req = 534 ohms
d) Ic = 25 mA = 0.015 A
e) I = e/(Ra + Rc) = 12/600 = 0.02 A
Vc = I*Rc = 0.02*200 = 4v
Q = Vc*C = 4*2*10^-6 = 8*10^-6 C
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