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1. At the instant shown, how does the magnetic flux enclosed by each loop compar

ID: 2295088 • Letter: 1

Question



1. At the instant shown, how does the magnetic flux enclosed by each loop compare?


2. Which loop has a larger induced voltage?


3. What is the direction of the induced current?



Consider the situation drawn below. At the instant shown two wire loops are exiting a region of uniform magnetic field. The top loop is moving to the left with speed v and the bottom loop is moving to the right also with speed v. The top loop is twice the length and half the width of the bottom loop. The effects of the loops on each other can be ignored.

Explanation / Answer

1)
magnetic flux = B*A

here B is constant in both the loops.

But area(effective area) of upper loop is > area(effective area) of lower loop

so, magnetic flux through upper loop > magnetic flux through lower loop


3) when the upper loop comes out from magnetic field the flux through the loop decreases.

According to lenz's law the induced current opposes the chnage in flux. it means it tris to increase the magnetic flux.

when induced current flows in counter clock wise direction it prodces a mgnetic filed out of the page.


so,

The direction of induced current in upper loop is counter clockwise


The direction of induced current in lower loop is counter clockwise