Need help calculating #1 C and D using the equation written at the top of the pa

Question

Need help calculating #1 C and D using the equation written at the top of the page, thank you!! Modern Experimental Chemistry Chemistry 153 Questions: 1. Determine the equation of the best-fit line through your data for the plot of [KIO,] vs 1/t in the form y = mr + b. Using your equation, fill in the following. Equation: 9:050ex-aaica -- a. m (slope) 9.050S b. b (y-intercept) c. Using your equation, what is the expected inverse time at which [KIo,]-25x10 M? What is the expected reaction time interval? d. If the time for the reaction to occur is 55 seconds, what is the molar concentration of KIO,? 2. What can you conclude about the effect on the reaction time interval of increasing the concentration of sulfite ion while holding the concentration of iodate ion constant? Which two mixed solutions did you use to determine this? 3. What is the relationship of reaction time interval to temperature? Which two mixed solutions did you use to determine this?

Explanation / Answer

Ans. In the graph, Y-axis indicates 1/time and X-axis depicts concentration. That is, according to the trendline (linear regression or standard curve equation) equation y = 9.0505x – 0.0159 obtained from the graph, one (1/time) unit (1 Y = Y) is equal to 9.0505 units on X-axis (concentration) minus 0.0159.

#c. Given, [KIO3] = x = 2.5 x 10-3

Putting x = 2.5 x 10-3 in trendline equation-

            y = 9.0505 (x) – 0.0159

            Or, (1/t) = 9.0505 (2.5 x 10-3) – 0.0159 = 0.0226 – 0.0159 = 0.0067

            Hence, (1/t) = 0.0067 s-1

Therefore, inverse time (1/t) for the reaction = 0.0067 s-1

# Expected reaction time interval, t = 1 / (0.0067 s-1) = 149.25 s

#d. Given, t = 55 seconds

Or, y = 1/t = 1/ 55s = 0.0182 s-1

Now, putting y = (1/t) = 0.0182 in trendline equation-

            0.0182 = 9.0505x – 0.0159

            Or, x = (0.0182 + 0.0159) / 9.0505 = 0.0341 / 9.0505

            Or, x = 3.77 x 10-3

Therefore, x = [KIO3] corresponding to 55 sec time interval = 3.77 x 10-3 M

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