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1. A wire of length L is fixed at both ends. Which of the options in figure 1 re

ID: 2294535 • Letter: 1

Question

1. A wire of length L is fixed at both ends. Which of the options in figure 1 represents the stationary wave with the longest wavelength that can be established in this wire?

Answer:______

3. Which of the options in figure 1 corresponds to the second harmonic, i.e, the stationary wave with the second longest wavelength that can be established in this wire?

Answer:______

Answer:______

Let us assume that the speed of the wave in our string is v. Write an experience for f1, the frequency of the first harmonic as a function of L and v.

f1= <equation 1>

f1=

Equation 3 will be useful during the lab and to answer the next three questions

5. Two identical wires A and B are subject to tension. The tension in wire A is ___times larger than that in wire B. Find the ratio of the frequencies of the first harmonic in these two wires, fA1/fB1

6. Two wires A and B are subject to the same tension, but A has___ times the mass per cm than wire B, Find the ratio of the frequencies of the first harmonic in these two wires. fA1/fB1

7. Two wires A and B are subject to the same tesion and have the same mass per unit length. The length of wire A is______ times that of wireB. Find the ratio of the frequencies of the first harmonic in these two wires, fA1/fB1

Please provide all the answers, explanations would be better. Thank you so much!!!!!!!!!!!

Explanation / Answer


1) C

2) lamda1 = 2*L

3) A

4) lamda2 = L

f1 = (v/2*L) = sqrt(T/mue)/2*L

f2 = 2*V/(2*L) = sqrt(T/mue)/L


5)

if TA = n*TB

then, fA1/fB1 = sqrt(n)


6)
if mA = n*mB

then, fA1/fB1 = sqrt(1/n)

7)

if LA = n*LB

then, fA1/fB1 = n