A charged particle, with charge +Q, is moving near a current carrying wire with

Question

A charged particle, with charge +Q, is moving near a current carrying wire with the direction of the velocity as shown. What is the direction of the magnetic force on the moving charge due to the wire?

Two long parallel wires are carrying currents I1 and I2 as shown. I1 lies along the x-axis, at y = 0, and I2 is at y = 8 cm.

If I1 = 5.75 I2, at what point on the y-axis will the total magnetic field be zero?

Give your answer in cm to three digits.

Two long parallel wires are carrying currents I1 = 880 A and I2 = 130 A as shown. I1 lies along the x-axis, at y = 0, and I2 is at y = 3.1 x 10-3 m.

What is the magnitude of the total magnetic field half-way between the two wires?

Give your answer in Tesla to three significant digits.

A current-carrying wire is held stationary near a conducting loop as shown in the picture. The loop and wire lie in the same vertical plane (view the screen or paper with the picture verically) so that if the loop is released if will fall to towards the bottom of the picture.

If the loop is released, what direction will the induced current in the loop flow? Consider a time shortly after the loop is released as it is moving downwards.

Explanation / Answer

[1]

into the plane of (F=Q*(V X B))

[2]

( I1 / I2 ) = ( r1 / r2 ) ( B = ( mu_o*I )/2*pie*r )

therefore at y=6.814 cm

[3]

magnetic fields in opposite directions (right hand thumb rule)

B = ( mu_o*I )/2*pie*r

I B I = 0.0968 tesla

[4]

it flows clockwise as seen from top (since the magnetic field is decreasing as it falls induces the field such a way that the field increases into the plane therefore clockwise)

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