Electric charge is distributed uniformly along a thin rod of length a , with tot
ID: 2290611 • Letter: E
Question
Electric charge is distributed uniformly along a thin rod of length a, with total charge Q. Take the potential to be zero at infinity. Find the potential at the following points: (the figure (Figure 1) ).
Part A
Find the potential at the point P, a distance x to the right of the rod.
Express your answer in terms of the given quantities and appropriate constants.
SubmitMy AnswersGive Up
Part B
Find the potential at the point R, a distance y above the right-hand end of the rod.
Express your answer in terms of the given quantities and appropriate constants.
SubmitMy AnswersGive Up
Part C
In part A, what does your result reduce to as x becomes much larger than a?
Express your answer in terms of the given quantities and appropriate constants.
SubmitMy AnswersGive Up
Part D
In part B, what does your result reduce to as y becomes much larger than a?
Express your answer in terms of the given quantities and appropriate constants.
Electric charge is distributed uniformly along a thin rod of length a, with total charge Q. Take the potential to be zero at infinity. Find the potential at the following points: (the figure (Figure 1) ).
Part A
Find the potential at the point P, a distance x to the right of the rod.
Express your answer in terms of the given quantities and appropriate constants.
V =SubmitMy AnswersGive Up
Part B
Find the potential at the point R, a distance y above the right-hand end of the rod.
Express your answer in terms of the given quantities and appropriate constants.
V =SubmitMy AnswersGive Up
Part C
In part A, what does your result reduce to as x becomes much larger than a?
Express your answer in terms of the given quantities and appropriate constants.
V =SubmitMy AnswersGive Up
Part D
In part B, what does your result reduce to as y becomes much larger than a?
Express your answer in terms of the given quantities and appropriate constants.
V =Explanation / Answer
part a)
V=(kQ/a)ln((x+a)/x)
part b)
dV=kdq/dr
V=kQln((y2+a2)1/2-y)
part c)
x>>>>a
then part a
V=(kQ/a)ln1
V=0
part d)
y>>>>a
V=kQln0=infinite
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.