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THANK YOU FOR MAKING THE ANSWERS CLEAR SO THAT I CAN RATE YOU ACCORDINGLY, AS SO

ID: 2289663 • Letter: T

Question

THANK YOU FOR MAKING THE ANSWERS CLEAR SO THAT I CAN RATE YOU ACCORDINGLY, AS SOON AS I GET A CHANCE.

A rocket with a mass of 59,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is 6,000 m/s. If the rocket is fired vertically upward from the surface of the Earth, determine its height after 944 kg of its total fuel load has been consumed. Since the mass of fuel consumed is small compared to the total mass of the rocket, you can consider the mass of the rocket to be constant for the time interval of interest.
m

Explanation / Answer

Thrust = -uR

u = speed of exhaust gases relative to the rocket

R = rate of mass ejection

Thrust = 150x6000 = 900000 N (upwards)

t = 944/150 = 6.293 s

Wt of the rocket = 59000g (downwards)

equation is Thrust - 59000g = 59000a

=> 900000 - 578200 = 61000a => a = 5.275 m/s