Equipotential Surfaces in a Capacitor Part A Is the electric potential energy of
ID: 2288949 • Letter: E
Question
Equipotential Surfaces in a Capacitor
Part A
Is the electric potential energy of a particle with charge q the same at all points on an equipotential surface?
Is the electric potential energy of a particle with charge the same at all points on an equipotential surface?
SubmitHintsMy AnswersGive UpReview Part
Correct
For a particle with charge q on an equipotential surface at potential V, the electric potential energy has a constant value qV.
Part B
What is the work required to move a charge around on an equipotential surface at potential V with constant speed?
SubmitHintsMy AnswersGive UpReview Part
Part C
What is the work done by the electric field on a charge as it moves along an equipotential surface at potential V?
SubmitHintsMy AnswersGive UpReview Part
Part D
The work WE done by the uniform electric field E? in displacing a particle with charge q along the path d? is given by
WE=qE? ?d? =q|E? ||d? |cos?,
where ? is the angle between E? and d? . Since in general, E? is not equal to zero, for points on an equipotential surface, what must ? be for WE to equal 0?
Express your answer in radians.
SubmitMy AnswersGive Up
Now assume that a parallel-plate capacitor is attached across the terminals of a battery as shown in (Figure 1) . The electric field E? in the region between the plates points in the negative z direction, from higher to lower voltage.
Part E
This question will be shown after you complete previous question(s).
Part F
This question will be shown after you complete previous question(s).
Provide FeedbackContinue
Figure 1 of 1
Yes NoExplanation / Answer
1. yes
2. Always remember work done across equipotential surface is always ZERO because we know that W= qdV and here dV=0.
3. Also zero.
4. as we know here WE=0 hence from W= Ed cos theta here costheta=0 and theta=90 deg.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.