Sammy threw a 0.06 kg ball at an angle such that the downwards initial velocity

Question

Sammy threw a 0.06 kg ball at an angle such that the downwards initial velocity is 4.0 m/s and the horizontal initial velocity is 8.0 m/s. Using 10 N/kg for the magnitude of g, the upward direction as positive, and assuming that the ball does not reach ground,

a) what is in m/s the vertical component of the velocity of the ball 0.50 seconds after it was thrown?

b) what is in m/s the horizontal component of the velocity of the ball 0.50 seconds after it was thrown?

c) what is in m/s2 the vertical component of the acceleration of the ball 0.50 seconds after it was thrown?

d) what is in m/s2 the horizontal component of the acceleration of the ball 0.50 seconds after it was thrown? e) what is in Newtons the net force acting on the ball 0.50 seconds after it was thrown?

Explanation / Answer

Part A)

Gravity plays a part here, so...

vf = vo + at

vf = -4 + (-10)(.5)

vf = -9 m/s (The negative indicates the downward direction)

Part B)

Velocity in the x direction does not change since gravity only acts in the vertical

Thus it will still be 8 m/s

Part C)

-10 m/s2 (Again negative only indicates direction is downward)

Part D)

0 m/s2 since gravity only acts vertically

Part E)

The force is the weight

F = mg

F = .06(10)

F = .6 N

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