help from anywhere 1. A completely ionized beryllium atom (net charge = +4e) is
ID: 2288096 • Letter: H
Question
help from anywhere
Explanation / Answer
1. KE = eV
kE = 4 *1.67 e-19 * 6
KE = 24 eV ---> option e
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2. W = U = vq
but V = Ed
so W = Edq
W = 150 * 0.25 * 4 e-6
W = -1.5 * 10^-4 ---> option B
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3. V = Ed
E = 50/0.1
E = 500 V/m ---> option d
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4. W = Vq
W = 500* 1000 e-6
W = 0.05 J option B
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apply V = KQ/r
Va/Vb = rb/ra
Va/Vb = 0.0012/0.001
Va/ Vb = 1.2 option C
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