sapling earning Three people pull simultaneously on a stubborn donkey. Jack pull

Question

sapling earning Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 83.9 N, Jill ulls with 67.1 N in the northeast direction, and Jane pulls to the southeast with 137 N. (Since the donke with such people, who can blame it for being stubborn?) Find the magnitude o the net force the people exert on the donkey. Number What is the direction of the net force? Express this as the angle from the east direction between 0 and 90 with a positive sign for north of east and a negative sign for south of east. Number

Explanation / Answer

forces acting in the horizontal direction

Fx= Fjack+Fjill cos(theta)-Fjane cos(theta) =83.9+67.1 cos(45)-137*cos(45)= 34.4807 N

Foces in the vertical direction

=Fjill sin (theta) -Fjane sin(theta)

=67.1sin(45)- 137sin(45)

Fy= -49.4193 N

the direction is

the net force is

Fnet = sqrt(Fx^2+Fy^2) ==60.21 N

B)

the direction is -55.09 degree

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