(Figure 1) In the figure are shown three capacitors with capacitances C 1=6.00 ?

Q: Figure 1) In the figure are shown three capacitors with capacitances C 1=6.00 ?

a) Charge on C2 Q2=Q*(C2/C1+C2) 40=Q*(3/3+6) Q=120 uC Charge on C1 is Q1=120-40=80uC b) Q3=Q=120 uC c) equivalent capacitance Ceq=(C1+C2)*C3/(C1+C2+C3)=(6+3)*5/(6+3+5) Ceq=3.2 uF Voltage Vab=Q/C =120/3.2= 37.3Volts

ID: 2286473 • Letter: #

Question

(Figure 1) In the figure are shown three capacitors with capacitances C1=6.00?F,C2=3.00?F,C3=5.00?F. The capacitor network is connected to an applied potential Vab. After the charges on the capacitors have reached their final values, the charge Q2 on the second capacitor is 40.0 ?C.

1. What is the charge Q1 on capacitor C1? Express your answer in microcoulombs.

2. What is the charge on capacitor C3? Express your answer in microcoulombs to three significant figures.

3. What is the applied voltage, Vab? Express your answer in volts to three significant figures.

Explanation / Answer

Charge on C2

Q2=Q*(C2/C1+C2)

40=Q*(3/3+6)

Q=120 uC

Charge on C1 is

Q1=120-40=80uC

Q3=Q=120 uC

equivalent capacitance

Ceq=(C1+C2)*C3/(C1+C2+C3)=(6+3)*5/(6+3+5)

Ceq=3.2 uF

Voltage

Vab=Q/C =120/3.2= 37.3Volts

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(Figure 1) In the figure are shown three capacitors with capacitances C 1=6.00 ?

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