MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEX Chapter 07, Problem 0

Question

MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEX Chapter 07, Problem 05 A volleyball is spiked so that its incoming velocity of +2.09 m/s is changed to an outgoing velocity of -10,4 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball? 2 Number Units the tolerance is +/-2% 2 Click if you would like to show work for this question Open Show Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less. copyright 2000-2015 by John Wiley s Sons, Inc. or related companies. All rights reserved,

Explanation / Answer

impulse=F(t2-t1) to be simply defined,

therfore ,impulse = m(v2-v1)

given , m=0.35 kg , v2=-10.4 (outgoing velocity) , v1=2.04 (incoming velocity),

impulse = 0.35*(-10.4-2.04) =4.284 (kg.m)/s

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