2/2/55, 634 AM 1. For anayzing optical problems involving the eye, what quantity

Question

2/2/55, 634 AM 1. For anayzing optical problems involving the eye, what quantity is fixed (for seeing something in focus)? A) Both f and s B) Both s and s C) The focal length f D) The image distance s E) Both f and s F) The object distance s 2. A diverging lens has a focal length of 20 cm. Its power in diopters is: A) 0.20 8)-0.20 C)0.05 D) 20 E) -5 F)-20 G) 5 H)-0.05 correct for myopla you need alens; to correct for hyperopia you need a A) diverging, diverging B) diverging, converging C) converging, diverging D) converging, converging 3. Tocorrect for myopia you need a- lers; to correct for hyperopia you need a lens -than the Corrective lenses object. For hyperopia, this image is- 4· create a image that is seen by the eye. For myopia, this image is than the object. A) virtual, closer, farther B) real, closer, closer C) virtual, farther, farther D) virtual, closer, closer E) virtual, farther, closer F) real, farther, farther G) real, farther, closer H) real, closer, farther 5. For "normal vision", the near points and far points are: 5. For rormal vision, the near points and far points are: A) 25 cm, 100 cm B)10cm, 25 C)0cm, 25cm D) 25 cm, 25 cm E) 25 cm, infinity 6· The magnty ofthe refraction that occurs in the eye happens: A) inside the lens B) at the rear surface of the lens C) at the front surface of the cornea Page 1 of 3

Explanation / Answer

1) image distance so D)

2) power = 1/f = 1/-0.2 = -5

so E)

3) myopia, diverging

hoperopia converging

so B)

4)

virtual, farther, closer

E)

5)
near point is 25 cm
far is infinity

so E)

6) front surface so C)

7) hyperopia is far sightedness

shift close objects to the near point

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