7. If all the charges are 15 cm from the origin (the crossing point of the verti

Question

7. If all the charges are 15 cm from the origin (the crossing point of the vertical and horizontal lines) in the above figure and Q = +3.0 mu C, then calculate the magnitude of the net force on a charge of +Q placed at the origin. A)22.8N B) 10.2 N C) 26.0 N D) 187 N E) none of the above 8. Three charges are located at 100-m intervals along a horizontal line: a charge of -3.0 C on the left, 2.0 C in the middle, and 1.0 C on the right. What is the electric field is on the horizontal line halfway between the -3.0 C and 2.0 C charges? A) 2.2 x 10^7 N/C to the left B) 1.8 x 10^7 N/C to the right C) 1.8x 10^7N/C to the left D) 3.2 x 10^6 N/C to the right E) 4.0 x 10^6 N/C to the left

Explanation / Answer

7) first do y direction

4 q will push down and -2Q will put down

so they add

F = k Q 6Q/r^2 = 9.0E9*6*3.0E-6^2/0.15^2= 21.6 N

now x direction

Q pushes right and -3Q pulls right so they add

F = k Q 4Q/r^2 = 9.0E9*4*3.0E-6^2/0.15^2 =14.4

mag = sqrt(21.6^2 + 14.4^2)= 26.0 N

so C)

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