I am not really getting this material and my instructor is not helping. Can you
ID: 2285553 • Letter: I
Question
I am not really getting this material and my instructor is not helping. Can you show me the steps to figure out this problem?
1. If q=2.0 uc and each charge is seperated from the nearest other charge by a distance of 20 cm. Find the net electric force (magnitude and direction) on the middle charge in each case.
Diagram (a)
Diagram (b)
Diagram (c)
2. In diagram C, find the net electric force (magnitude and direction) on the bottom charge.
a) +GO G sas ra B) to solo I. & O ON No A. 9N -q O O +4Explanation / Answer
r = 20 cm = 0.2 m
a)
Fnet = k*q^2/r^2 - k*q^2/r^2 = 0
#b)
Fnet = k*q^2/r^2 + k*q^2/r^2 = 2*k*q^2/r^2 = (2*9e9*2e-6*2e-6)/(0.2*0.2) = 1.8 N towrds left
#c)
Fx = k*q^2/r^2 = (9e9*2e-6*2e-6)/(0.2*0.2) = 0.9 N
Fy = k*q^2/r^2 = (9e9*2e-6*2e-6)/(0.2*0.2) = 0.9 N
magnitude = Fnet = sqrt(F^2+Fy^2) = 1.27 N
direction = 45 with the horizantal in clockwise direction
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