Problem 16.31 An electron is released from rest in a uniform electric field and
ID: 2285290 • Letter: P
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Problem 16.31 An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 120m/s2 . Part A What is the magnitude of the electric field? E = N/C Part B What is the direction of the electric field? What is the direction of the electric field? to the south to the west to the north to the east Problem 16.31 An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 120m/s2 . Part A What is the magnitude of the electric field? E = N/C Part B What is the direction of the electric field? What is the direction of the electric field? to the south to the west to the north to the east Problem 16.31 Problem 16.31 An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 120m/s2 . An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 120m/s2 . An electron is released from rest in a uniform electric field and accelerates to the north at a rate of 120m/s2 . Part A What is the magnitude of the electric field? E = N/C Part B What is the direction of the electric field? What is the direction of the electric field? to the south to the west to the north to the east Part A What is the magnitude of the electric field? E = N/C Part A What is the magnitude of the electric field? E = N/C E = N/C E = N/C Part B What is the direction of the electric field? What is the direction of the electric field? to the south to the west to the north to the east Part B What is the direction of the electric field? What is the direction of the electric field? to the south to the west to the north to the east What is the direction of the electric field? to the south to the west to the north to the east What is the direction of the electric field? to the south to the west to the north to the east What is the direction of the electric field? to the south to the west to the north to the eastExplanation / Answer
a)
. F = ma = qE
9.1e-31kg * 120m/s
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