1. A skier traveling at 37.9 m/s encounters a 18.3 degree slope. If you could ig
ID: 2285040 • Letter: 1
Question
1. A skier traveling at 37.9 m/s encounters a 18.3 degree slope. If you could ignore friction, to the nearest meter, how far up the hill does he go?
2. If the coefficient of kinetic friction in the previous problem was actually 0.12 and the slope 30 degrees, to the nearest meter how far up the hill does he go?
3. You have a mass of 66 kg and are on a 53-degree slope hanging on to a cord with a breaking strength of 130 newtons. What must be the coefficient of static friction to 2 decimal places between you and the surface for you to be saved from the fire?
Explanation / Answer
KE at bottom = PE at top
0.5*m*v^2 = m*g*L*sin18.3
L = 233.4 m
2)
KE - Wf = PE
0.5*m*v^2 - u*m*g*cos30*L = m*g*L*sin30
0.5*v^2 - u*g*L*cos30 = g*L*sin30
0.5*v^2 = g*L*(sin30 + u*cos30)
L = 121.35 m
3) T + u*m*g*cos53 = m*g*sin53
u = 0.99
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