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The figure (Figure 1) shows cross sections of five closed surfaces S 1, S 2, etc

ID: 2284074 • Letter: T

Question

The figure (Figure 1) shows cross sections of five closedsurfaces S1, S2, etc. Assume that q1 = 5.4?C , q2 = 8.6?C , q3 = 1.1?C , q4 = 7.6?C , q5 = 7.2?C , and q6 = 10.4?C .

Part A

Find the net electric flux passing through the surface S1.

Express your answer using two significant figures.

0

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Correct

Part B

Find the net electric flux passing through the surface S2.

Express your answer using two significant figures.

8.85

The figure (Figure 1) shows cross sections of five closedsurfaces S1, S2, etc. Assume that q1 = 5.4?C , q2 = 8.6?C , q3 = 1.1?C , q4 = 7.6?C , q5 = 7.2?C , and q6 = 10.4?C .

Part A

Find the net electric flux passing through the surface S1.

Express your answer using two significant figures.

? =

0

  N?m2/C  

SubmitMy AnswersGive Up

Correct

Part B

Find the net electric flux passing through the surface S2.

Express your answer using two significant figures.

? =

8.85

Explanation / Answer

Let's solve all five parts at the same time.

Net electric flux of a closed surface is, by Guass's law, equivalent to the charge that surface encloses divided by the permittivity of free space, e_0. Therefore, all you have to do to calculate flux is

Flux = Charge enclosed / 8.85 x 10^(-12)

A. q in S1 = 0

flux = 0

B. q in S2 = q1 + q2 - q5 = 14 - 7.2 = 6.8

flux = 6.8*10^-6/8.85*10^-12

C. q in S3 = q2 + q3 - q6 = 9.7 - 10.4 = -0.7

flux = -0.7*10^-6 / 8.85*10^-12

D. q in S4 = 7.4 - 7.2 = 0.2

flux = 0.2*10^-6 / 8.85*10^-12

E. q in S5 = 22.7- 17.6 = 5.1

flux = 5.1*10^-6 / 8.85*10^-12

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