The figure shows a closed Gaussian surface in the shape of a cube of edge length

Question

The figure shows a closed Gaussian surface in the shape of a cube of edge length 1.8 m, with one corner at x1 = 4.8 m,y1 = 4.3 m. The cube lies in a region where the electric field vector is given by Efield=( -2.2 )i -(4.4 y2)j +(2.6)k  N/C, with y in meters. What is the net charge contained by the cube?

I did this problem and found that since there were constants on the x and z components of the E-field, those fluxs cancelled out. I found the Right side flux to be 89.1 (Nm^2/C) (which is correct according to the tutorial) and the left side of the cube to be -263.593 which is also correct according to the tutorial. I finished the problem by multiplying the sum of these two by epsilon naught (which I believe to be 8.85E-12) to get an answer of -1.54E-9 which is wrong. What did I do wrong?

Explanation / Answer

E=q/e0

we are given E

we can find the magnitude of E

E=sq root of (Ex2+Ey2+Ez2)

we know e0

we can find q

we are given components of E too

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