1. Three identical point charges of charge q = 7.3 ?C are placed at the vertices
ID: 2283302 • Letter: 1
Question
1.
Three identical point charges of charge q = 7.3 ?C are placed at the vertices (corners) of an equilateral triangle. If the side of triangle is a = 5.2m, what is the magnitude, in N/C, of the electric field at the point P in one of the sides of the triangle midway between two of the charges?
2.
Four charges are placed at the corners of a square. If q1 = 44.0 x 10-9 C, q2 = -24.0 x 10-9 C, q3 = 26.0 x 10-9 C, q4 = -46.0 x 10-9 C and the side of the square is a = 0.32 m. What would be the magnitude of the electrical field in the middle of the square? Answer in units of N/C.
3.
Four charges are placed at the corners of a rectangle. If q1 = 52.0 x 10-9 C, q2 = -46.0 x 10-9 C, q3 = 52.0 x 10-9 C, q4 = -80.0 x 10-9 C and the side of the rectangle are a = 0.36 m, and b=2a/3. What would be the magnitude of the electrical field in the middle of the rectangle? Answer in units of N/C
4
Consider a thin spherical shell of radius 23.4cm with a total charge of 4.4?C distributed uniformly on its surface. Find the electric field, in N/C, at a radius of 35.5cm from the center of the charge distribution.
5.
The total electric flux through a closed surface in the shape of a cylinder is -7.37x105Nm2/C. What is the net charge, in ?C, within the cylinder?
Explanation / Answer
1> The electric field due to the two charges adjacent to the point is zero as the field created by them is equal and oppodite.
So, Electric Field=kq/r2=9x109x7.3x10-6/2.62x3=3.24x103N/C
2> a=0.32m
Electric field due to 2 opp. charges=9x109x18x10-9x2/.322=3164N/C
Electric field due to 2 opp. charges=9x109x22x10-9x2/.322=3867N/C
Electric field= root(31642+38672)=4996N/C
3> Length of diagonal=0.4327m
Electric field=9x109x34x10-9/.216352=6537N/C
4> Electric field=9x109x4.4x10-6/.3552=314x103N/C
5>Net electric charge=7.37x105x8.85x10-12=6.52245x10-6C
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