o. Particles in a gold ring. You have a pure (24-karat) gold ring with mass 17.7
ID: 2283043 • Letter: O
Question
o. Particles in a gold ring. You have a pure (24-karat) gold ring with mass 17.7 g. Gold has an atomic mass of 197 g/mol and an atomic number of 79. (a) How many protons are in the ring, and what is their total positive charge? (b) If the ring car- 1 ries no net charge, how many electrons are in it? ries no net charge. how many electrons are in i? ·Two equal point charges of +3.00 × 10-6 C are placed 0.200 m apart. What are the magnitude and direction of the 1 force each charge exerts on the other? .At what distance would the repulsive force between two electrons have a magnitude of 2.00 N? Between two protons?Explanation / Answer
1.
N(no of gold atoms in17.7g)=m/mw x NA=17.7/197 x 6.022x1023=0.54xx1023
(a) No of protons=NZ=0.54xx1023x79=42.66xx1023
charge of protons=NZe=42.66xx1023x1.6x10-19=6.826x105C
(b)No of electrons for zero net charge=NZ=0.54xx1023x79=42.66xx1023
2.
F=kq1q2/d2
F=9x109x(3x10-6/0.2)2
F=2.025N
force is going to be repulsive so each will exert force in the direction of another
3
F=kq1q2/d2
2=9x109x(1.6x10-19/d)2
d=1.6x10-19sqrt(9x109/2)
d=1.07x10-14m(for both electrons and protons since charge on both are same)
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