Sam wraps a srting around the outside of a 0.040 m-radius 0.20 kg solid cylinder
ID: 2281627 • Letter: S
Question
Sam wraps a srting around the outside of a 0.040 m-radius 0.20 kg solid cylinder and uses it like a yo-yo. When released, the cylinder accelerates downwards at 2/3 g.
(a) draw a force diagram for the cylinder and apply the translational form of Newton's second law to the cylinder in order to determine the force that the string exerts on the cylinder.
(b) determine the rotational inertia of the solid cylinder
(c) apply the rotational form of Newton's second law and determine the cylinder's rotational acceleration
Explanation / Answer
a) T - m g = ma
T = mg + ma = 0.2*(9.81 -2/3*9.81)= 0.654 N
b)
I = 1/2 M R^2 = 0.5*0.2*0.04^2= 1.6E-4
c)
torque = I alpha
alpha = torque/I = 0.04*0.654/1.6E-4= 163.5 rad/s^2
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