A liquid of density 1.11 x 10^3 kg/m^3 flows steadily through a pipe of varying

Question

A liquid of density 1.11 x 10^3 kg/m^3 flows steadily through a pipe of varying diameter and height. At location 1 along the pipe the . flow speed is 9.99 m/s and the pipe diameter is 1 1.3 cm. At location 2 the pipe diameter is 17.5 cm. At location I the pipe is 9.03 m higher than it is at location 2. Ignoring viscosity, calculate the difference between the fluid pressure at location 2 and the fluid pressure at location 1. Number 9.882 X 10^4 Pa Incorrect. . ______________ You appear to have ignored the flow speeds.

Explanation / Answer

Bernoulli's equation problem
P1 + 1/2*rho*v1^2 + rho*g*h1 = P2 + 1/2*rho*v2^2 + rho*g*h2

Solve for P2-P1
P2-P1 = 1/2*rho*(v2^2 - v1^2) + rho*g*(h2-h1)

Now use continuity to find v2
From the other problem I helped you with
v1*d1^2 = v2*d2^2
v2 = v1*d1^2/d2^2

v2 = 9.99 m/s * (11.3 cm)^2 / (17 cm)^2 = 4.41 m/s

Note: Sometime you don't need to covert dimensions if they are canceling, like above.

Anyways, since h1 is higher than h2, (h2-h1) = -8.03 m

Just plug in your numbers.

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