I am having a difficult time figuring this out... Two capacitors Cf~=7.4 mu F, C

Question

I am having a difficult time figuring this out...

Two capacitors Cf~=7.4 mu F, C2 = 18.1 mu F are charged individually to V1 = 19.5 V, V2=^3.6 V. The two capacitors are then connected together in parallel with the positive plates together and the negative plates together. Calculate the final potential difference across the plates of the capacitors " 8.214V You are correct. Your receipt no. is 155-2993 Calculate the amount of charge (absolute value) that flows from one capacitor to the other when the capacitors are connected together. |83.51 nC Pick one capacitor, you know the charge on this capacitor before they were connected. Now that you know the potential difference after they are connected - remember the potential drop is the same for both of them - you can calculate the charge: Q=CV. You have to calculate the difference of Q before and after. once they are connected. Previous Tries Tries 6/19 Previous Tries Submit Answer Incorrect. By how much (absolute value) is the total stored energy reduced when the two capacitors are connected? Submit Answer Tries 0/19

Explanation / Answer

B) initia charge on plate = 144. uC

final charge = 8.214* 7.4 = 60.78

charge flown = 83.51 uC its micro coloumb

Initia energy = 1/2 * C*V^2 = 1.52*10^-3 J

Final energy = 8.56*10^-4 J

Change in energy = 6.63 *10^-4 Joule

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