just the period of motion and and explanation as to why it is clockwise A partic
ID: 2280963 • Letter: J
Question
just the period of motion and and explanation as to why it is clockwise
A particle of charge 25 mu C and mass 1.4 times 10-15 kg moves at a speed of 1980 m/s, and its velocity vector lies in the x-y plane. There is a magnetic field of magnitude 0.90 T along the +z direction. The magnetic force on the particle causes the particle to move in a circle that lies in the x-y plane. Find the radius of this circle. Find the period of the motion. If the particle is moving parallel to +y at t = 0, is the circular motion clockwise or is it counterclockwise as viewed from along the +z axis?Explanation / Answer
T = 2*pie*m/qB = 2*3.14*1.4*10^(-15)/(25*10^(-6) * 0.90) = 0.39 * 10^(-9) = 3.9*10^(-10) s
it is clockwise as we apply the right hand rule and move the curl of our fingers in the direction of velocity to magnetic field (i.e, +y to +z) the the thumb direct in the direction of resulting force which is +x direction. continuing it in the same fashion we see the particle follows clockwise motion
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