please show steps! In the circuit in the figure, the capacitors are a initially

Question

please show steps!

In the circuit in the figure, the capacitors are a initially uncharged, the battery has no internal resistance, and the ammeter is idealized 25.0 n 15.00 15.0 HF 20.0 25.0 0.0 F 100.0 V 50.0 25.0 n A VW 15.0 (Hint: You may be intimidated by this circuit, but have faith that you can do this. Remember how capacitors behave at t 0 and as t infinity, and REDRAW the circuit at these two times based on that behavior! Then the problem is a snap.) (a) Find the reading of the ammeter just after the switch S is closed. Enter a number (b Find the reading of the ammeter after the switch has been closed for a very long time.

Explanation / Answer

a)

When switch was closed initially all the capacitors act as short circuit i.e as simple wire.so equivalent resistance

Req =75+15 +(50 || 25)

Req =75+15+(50*25/50+25)

Req =106.67 ohms

reading of ammeter is

I=V/Req =100/106.67

I=0.9375 A

b)

after long time switch has been closed capacitors act as open circuit ,so equivalent resistance

Req =25+75+25+25+15

Req =165 ohms

reading of ammeter is

I=V/Req =100/165

I=0.6061 A

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