You pick up a board of length 2.30 m and mass 11.50 kg. To do this, you exert a

ID: 2280800 • Letter: Y

Question

You pick up a board of length 2.30 m and mass 11.50 kg. To do this, you exert a force upward with your left hand a distance LL=0.483 m from the end of the board as shown, and you need to exert a force with your right hand a distance LR=0.174 m from the end of the board. Assume the board to be in static equilibrium and that the board is symmetrical with the mass evenly distributed.

What force does the right hand need to exert to keep the board in static equilibrium? (you need to get both the magnitude and the direction)

What is the magnitude of the force that the left hand needs to exert to keep the board in static equilibrium?

Explanation / Answer

the mass acts at a distace 2.3/2=1.15m

let F1 be force upwards with left hand

and F2 be force upwards with right hand

so by force balance we get

F1+F2=11.5

and by moment balance about end point we get

F1*(0.483)+F2*(0.174)-11.5*9.8*1.15

F1*(0.483)+F2*(0.174)=129.605

so from this two equation we get

F1=412.958N( force by left hand) (upward)

F2=401.458N (force by right hand )(downward)

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You pick up a board of length 2.30 m and mass 11.50 kg. To do this, you exert a

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