1. Light travelling through air is incident on a transparent material at an angl

Question

1. Light travelling through air is incident on a transparent material at an angle of 20.0 degrees and is refracted into that material at an angle of 16.0 degrees. Calculate index of refraction of the material.

2. Calculate the angle at which light would enter the air if it is incident on the surface of water (index of refraction 1.33) in a swimming pool from under the water at an angle of 19.0 degrees.

3. A diamond with an index of refraction 2.42 is held under water and light strikes the surface of the diamond from the water side at an angle of 34.0 degrees, what will be the angle of refraction of a light ray inside the diamond?

Explanation / Answer

apply na sinA = nb sin B

a. for air na = 1

so nb = 1* sin20/sin 16

nb = 1.24

b. sin A = 1.33* sin 19/1

sinA = 0.433

A = 25.65 deg

c. sin B = 1.33* sin 34/2.42

sin B = 0.307

B = 17.89 deg

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