1) Six 9.3??F capacitors are connected in parallel. What is the equivalent capac
ID: 2280426 • Letter: 1
Question
1) Six 9.3??F capacitors are connected in parallel.
What is the equivalent capacitance?
Ceq = ?F
What is their equivalent capacitance if connected in series?
Ceq = ?F
2) A circuit contains a single 260?pF capacitor hooked across a battery. It is desired to store three of two capacitors by adding a single capacitor to this one.
What would its value be?
C = pF
3) A power supply has a fixed output voltage of 12.0 V, but you need VT=5.0V for an experiment.
R2 = ?
What will the terminal voltage VT be if you connect a load to the 5.0V terminal, assuming the load has a resistance of 4.0? ?
VT = V
F capacitors are connected in parallel. What is the equivalent capacitance? What is their equivalent capacitance if connected in series? A circuit contains a single 260?pF capacitor hooked across a battery. It is desired to store three of two capacitors by adding a single capacitor to this one. What would its value be? A power supply has a fixed output voltage of 12.0 V, but you need VT=5.0V for an experiment. Using the voltage divider shown in the figure , what should R2 be if R1 is 16.0? What will the terminal voltage VT be if you connect a load to the 5.0V terminal, assuming the load has a resistance of 4.0? ?Explanation / Answer
a) Parallel
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If all the capacitors are in parallel, the result is as if they were resistors in series. Since they are all the same, you get 6*9.3 uF = 55.8uF
Series
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If all the capacitors are in series, the result is like resistors in parallel. Since they are all the same, you get
9.3 uF/6 = 1.55 uF
b) in a given time, this battery can supply a fixed charge (Q)
energy stored at constant charge is
E = Q^2/2C
it reveals that for storing 3 times higher energy, final capacitance of new elements (C1 & C2) [in the denominator] must decrease
>> the combination with can do this is > series combination of C1 & C2
1/C(final) = 1/C1 + 1/C2 = [C1+C2]/C1C2
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given >
3 E (old) = E(new)
3 Q^2/2C1 = [Q^2/2C(final)]
3/C1 = [C1+C2]/C1C2
3C2 = [C1+C2]
2C2 = C1
C2 = C1/2 = 260/2 = 130 pF
>>>>>>>>
so connect 130 pF capacitor in series with given capacitor
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