) What is the tangential acceleration of a bug on the rim of a 13.0-in.-diameter

Question

) What is the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 76.0 rev/min in 3.20 s?
1      m/s2

(b) When the disk is at its final speed, what is the tangential velocity of the bug?
2      m/s

(c) One second after the bug starts from rest, what is its tangential acceleration?
3      m/s2

(d) One second after the bug starts from rest, what is its centripetal acceleration?
4      m/s2

(e) One second after the bug starts from rest, what is its total acceleration?
5      m/s2 6      5      m/s2 6     

Explanation / Answer

a) 79 rev/min / 60 sec/min * 2? rad/rev / 3.50 s = 2.36 rad/s

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