The flexible loop in the figure below has a radius of 14.5 cm and is in a magnet

Question

The flexible loop in the figure below has a radius of 14.5 cm and is in a magnetic field of strength 0.158 T.



The loop is grasped at points A and B and stretched until it closes. If it takes 0.190 s to close the loop, find the magnitude of the average induced emf in it during this time.

A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B field (B is constant in time) and then back into a field free region to the left. The self inductance of the loop is negligible. When entering the field the coil experiences a magnetic force to the left. When leaving the field the coil experiences a magnetic force to the right. Upon entering the field, a clockwise current flows in the loop.

Explanation / Answer

average emf induced=delta(?)/delta(t)= B*delta(A)/delta(t) = 0.158*(pi*0.145^2 - 0.01)/0.19

= 0.04658 V= 46.58 mV

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