4. The reaction is second order in A. When [A]0 = 0.100 M, the reaction is 20.0%

Question

4. The reaction
is second order in A. When [A]0 = 0.100 M, the reaction is 20.0% complete in 35.9 minutes. Calculate the value of the rate constant (in L/min·mol). A) 6.96 10–2 B) 5.57 10–4 C) 1.57 D) 1.11 E) none of these

4. The reaction
is second order in A. When [A]0 = 0.100 M, the reaction is 20.0% complete in 35.9 minutes. Calculate the value of the rate constant (in L/min·mol). A) 6.96 10–2 B) 5.57 10–4 C) 1.57 D) 1.11 E) none of these

4. The reaction
is second order in A. When [A]0 = 0.100 M, the reaction is 20.0% complete in 35.9 minutes. Calculate the value of the rate constant (in L/min·mol). A) 6.96 10–2 B) 5.57 10–4 C) 1.57 D) 1.11 E) none of these

Explanation / Answer

Kt   = [1/[A]t - 1/[A]

t   = 35.9 minutes

20% complete meaning means 80% remaining

K*35.9 = [ 1/0.8*0.1 - 1/0.1]

K*35.9 = 12.5-10

K            = 2.5/35.9 = 0.0696   = 6.96*10^-2M^-1 min^-1

A)

6.96 10–2

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